190.5=15.b^2

Solution for 190.5=15.b^2 equation:

190.5=15.b^2

We move all terms to the left:

190.5-(15.b^2)=0

We get rid of parentheses

-15.b^2+190.5=0

We add all the numbers together, and all the variables

-15b^2+190.5=0

a = -15; b = 0; c = +190.5;
Δ = b2-4ac
Δ = 02-4·(-15)·190.5
Δ = 11430
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11430}=\sqrt{9*1270}=\sqrt{9}*\sqrt{1270}=3\sqrt{1270}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{1270}}{2*-15}=\frac{0-3\sqrt{1270}}{-30}
=-\frac{3\sqrt{1270}}{-30}
=-\frac{\sqrt{1270}}{-10}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{1270}}{2*-15}=\frac{0+3\sqrt{1270}}{-30}
=\frac{3\sqrt{1270}}{-30}
=\frac{\sqrt{1270}}{-10}
$